#### Answer

$12r^{8}s^{7}$

#### Work Step by Step

Use the product property for exponents $(a^{m} \times a^{n}=a^{m+n})$, as well as the associative and commutative property, to simplify $(-4r^{6}s^{2})(-3r^{2}s^{5})$:
$(-4r^{6}s^{2})(-3r^{2}s^{5})$
=$((-4)\times (-3))(r^{6}\times r^{2})(s^{2}\times s^{5})$
=$(12)(r^{6+2})(s^{2+5})$
=$(12)(r^{8})(s^{7})$
=$12r^{8}s^{7}$