Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.2 - Multiplication Properties of Exponents - Exercise Set - Page 710: 16

Answer

$36a^5b^{15}$

Work Step by Step

$(3a^3b^6)(12a^2b^9)=(3\times12)(a^3\times a^2)(b^6\times b^9)=36(a^{3+2})(b^{6+9})=36a^5b^{15}$
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