Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Cumulative Review - Page 730: 13

Answer

$\frac{13x}{30}$

Work Step by Step

Convert to like fractions and add the numerators. $\frac{2x}{15}+\frac{3x}{10}$ =$\frac{2x\times2}{15\times2}+\frac{3x\times3}{10\times3}$ =$\frac{4x}{30}+\frac{9x}{30}$ =$\frac{13x}{30}$
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