Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 1 - Section 1.8 - Introduction to Variables, Algebraic Expressions, and Equations - Exercise Set: 43


1: 16 ft 2: 64 ft 3: 144 ft 4: 256 ft

Work Step by Step

Substitute each value for t and solve. $16\times1^2=16\times1=16$ $16\times2^2=16\times4=64$ $16\times3^2=16\times9=144$ $16\times4^2=16\times16=256$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.