#### Answer

11

#### Work Step by Step

$3x^2+2x-5$ $\longrightarrow$ substitute
=$3(2^2)+2(2)-5$ $\longrightarrow$ resolve exponent; multiply
$3(4)+4-5$ $\longrightarrow$ multiply
$12+4-5$ $\longrightarrow$ solve
$=16-5=11$

Published by
Pearson

ISBN 10:
0321955048

ISBN 13:
978-0-32195-504-3

11

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