Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 1 - Section 1.8 - Introduction to Variables, Algebraic Expressions, and Equations - Exercise Set - Page 81: 32



Work Step by Step

$3x^2+2x-5$ $\longrightarrow$ substitute =$3(2^2)+2(2)-5$ $\longrightarrow$ resolve exponent; multiply $3(4)+4-5$ $\longrightarrow$ multiply $12+4-5$ $\longrightarrow$ solve $=16-5=11$
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