Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 1 - Review - Page 93: 108



Work Step by Step

$\frac{4\times8-1\times11}{3(9-2^{3})}$ =$\frac{32-11}{3(9-8)}$ =$\frac{21}{3(1)}$ =$\frac{21}{3}$ =7
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