Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 1 - Review - Page 93: 105



Work Step by Step

$(6-4)^{3}$$\times$[$10^{2}$$\div$(3+17)] =$2^{3}$$\times$($10^{2}$$\div$20) =8$\times$(100$\div$20) =8$\times$5 =40
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