Answer
$\frac{6y^{12}}{z^{2}}$
Work Step by Step
Use the distributive property and the exponent product rule ($x^{y}$ $\times$ $x^{z}$ = $x^{y+z}$). Then, use the negative exponent rule.
3 $\times$ 2 = 6
$y^{9}$$\times$$y^{3}$ = $y^{12}$
$z^{10}$ $\times$ $z^{-12}$ =$z^{-2}$
$\frac{6y^{12}}{z^{2}}$
