Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 9 - Measurement - 9.2 Measuring Area and Volume - Exercise Set 9.2: 52

Answer

The population density in 1980 was $25.0~people/km^2$

Work Step by Step

We know that $1~mi = 1.6~km$ Then: $1~mi^2 = 1.6~km\times 1.6~km = 2.56~km^2$ In 1980, the land area was $3,539,289~mi^2$. We can convert this area to units of $km^2$. $3,539,289~mi^2 = \frac{3,539,289~mi^2}{1}\times \frac{2.56~km^2}{1~mi^2} = 9,060,579.84~km^2$ We can find the population density in 1980. $\frac{226,545,805~people}{9,060,579.84~km^2} = 25.0~people/km^2$ The population density in 1980 was $25.0~people/km^2$
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