#### Answer

(a) The value of the annuity is $\$702,528$
(b) The interest is $\$542,528$

#### Work Step by Step

(a) This is the formula we use to calculate the value of an annuity:
$A = \frac{P~[(1+\frac{r}{n})^{nt}-1]}{\frac{r}{n}}$
$A$ is the future value of the annuity
$P$ is the amount of the periodic deposit
$r$ is the interest rate
$n$ is the number of times per year the interest is compounded
$t$ is the number of years
$A = \frac{P~[(1+\frac{r}{n})^{nt}-1]}{\frac{r}{n}}$
$A = \frac{(\$4000)~[(1+\frac{0.065}{1})^{(1)(40)}-1]}{\frac{0.065}{1}}$
$A = \$702,528$
The value of the annuity is $\$702,528$
(b) The total amount of money deposited into the annuity is $\$4000 \times 40$ which is $\$160,000$
The interest is the difference between the value of the annuity and the total amount deposited. We can calculate the interest.
$interest = \$702,528 - \$160,000 = \$542,528$
The interest is $\$542,528$