Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 7 - Algebra: Graphs, Functions, and Linear Systems - 7.3 Systems of Linear Equations in Two Variables - Concept and Vocabulary Check - Page 444: 5

Answer

Eliminate\[y\]by multiplying the first equation by 2 and second equation by\[-3\] and then add the equations.

Work Step by Step

Given equations are\[4x-3y=15\ \text{and 3}x-2y=10\]. To eliminate\[y\], first equation is multiplied by\[2\] and second equation is multiplied by\[-3\].Thus, \[\begin{align} & \left( 3x-2y=10 \right)\times -3 \\ & -9x+6y=-30 \\ \end{align}\] Now, add the above equation to the changed first equation to eliminate\[y\]. Hence, to eliminate\[y\], second equation is multiplied by\[-3\].
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