## Thinking Mathematically (6th Edition)

RECALL: The point $(x, y)$ has: x = directed distance of the point from the y-axis (positive when to the right of the y-axis, negative when to the left) y = directed distance of the point from the x-axis (positive when above the x-axis, negative when below) Thus, the given point is: 0 units from the y-axis (which means the point is on the y-axis) 3 units below the x-axis