Chapter 6 - Algebra: Equations and Inequalities - 6.3 Applications of Linear Equations - Exercise Set 6.3: 5

The number is 120.

Work Step by Step

step 1 Let x represent the unknown number in the problem. step 2 "$60\%$ of a number" = $\displaystyle \frac{30}{100}\cdot x=0.6x$ " ... $60\%$ of the number is added to the number" = $x+0.6x$ " the result is $192$" is written as " = $192$" step 3 The equation is $x+0.6x=192$ step 4 $x+0.6x=192\qquad$/simplify LHS $1.6x=192\qquad/\div 1.6$ $x=\displaystyle \frac{192}{1.6}=\frac{1920}{16}=120$ The number is $120$. step 5 Check the solution in the original wording of the problem. When 60% of 120, ($\displaystyle \frac{60}{100}\cdot 120=72),$ is added to the number (72+120) the result is 192. OK.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.