Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2 - Page 364: 119


To solve a proportion, use cross product principle

Work Step by Step

To solve a proportion, use cross product principle which is stated below, Let $\frac{a}{b}::\frac{c}{d}$ are in proportion then, $a\times d=b\times c$. That is product of means = product of extremes. Example: If $2:x::\ 5:8$ then find the value of x $2:x::\ 5:8$ Product of means $=$ product of extremes \[2\times 8=x\times 5\] This implies that, \[\begin{align} & x=\frac{2\times 8}{5} \\ & =\frac{16}{5} \end{align}\]
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