#### Answer

Shown below

#### Work Step by Step

(a)
The graph assigns anticipated salary on the x-axis and the percentage of college students on the y-axis.
From the provided graph, the desired value would be the point on the line curve whose x-coordinate 30.
Consider the given graph and locate the point on the curve against the anticipated starting salary. This can be seen below:
This shows the percentage of a college student as:
$p=22%$
Thus, the percentage of the student is 22%.
(b)
Consider the equation as follows:
$p=-0.01{{s}^{2}}+0.8s+3.7$
Now, substitute the value of $s$as $30 and find the value of$p$.
p=-0.01{{s}^{2}}+0.8s+3.7
=-0.01( 30^2+0.8( 30)+3.7
=-9+24+3.7
=18.7%
This shows the percentage of students who anticipated a starting salary of $30 thousand.
Compare the calculated value with the estimated value from the part (a). It is done by subtracting both values.
22-18.7=3.3
=3.3%
This shows that the calculated value of the formula is 3.3% less than the estimated value from the part (a).