## Thinking Mathematically (6th Edition)

Published by Pearson

# Chapter 6 - Algebra: Equations and Inequalities - 6.1 Algebraic Expressions and Formulas - Exercise Set 6.1 - Page 348: 65

#### Answer

-$2x^{2}$-9

#### Work Step by Step

2($3x^{2}$ -5) - [4($2x^{2}$ - 1) + 3] Step 1: Drop parentheses and multiply 2 and 4with each term and change the sign of each term in parentheses: 2($3x^{2}$ -5) = $6x^{2}$ -10 and 4($2x^{2}$ - 1) = $8x^{2}$ - 4 Step 2 Simplify inside brackets: -4+3 = -1 $6x^{2}$ -10- [$8x^{2}$ - 1] Step 3 drop brackets and change the sign of each term in brackets $6x^{2}$ -10- $8x^{2}$ +1 Step 4: Group like terms($6x^{2}$ -$8x^{2}$ ) - 10+1 Step 6: Combine the like terms ($6x^{2}$ -$8x^{2}$ )= -$2x^{2}$ So, final solution -$2x^{2}$-9

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