Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter Summary, Review, and Test - Review Exercises - Page 337: 139



Work Step by Step

To find the sixth term put \[n=6\] in the above formula, to get: \[\begin{align} & {{a}_{6}}={{a}_{1}}{{r}^{6-1}} \\ & =16\cdot {{\left( \frac{1}{2} \right)}^{5}} \\ & =16\cdot \frac{1}{32} \\ & =\frac{1}{2} \end{align}\] The sixth term of the geometric sequence is\[\frac{1}{2}\].
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.