Thinking Mathematically (6th Edition)

$\frac{1}{2}$
To find the sixth term put $n=6$ in the above formula, to get: \begin{align} & {{a}_{6}}={{a}_{1}}{{r}^{6-1}} \\ & =16\cdot {{\left( \frac{1}{2} \right)}^{5}} \\ & =16\cdot \frac{1}{32} \\ & =\frac{1}{2} \end{align} The sixth term of the geometric sequence is$\frac{1}{2}$.