## Thinking Mathematically (6th Edition)

On${{15}^{th}}$ day the person puts aside$\16,384$.
: The provided information can be modelled as a geometric progression with the following parameters: $a=1,\,r=2,\,n=15$ The fifteenth term is, \begin{align} & {{a}_{n}}=a{{r}^{n-1}} \\ & {{a}_{15}}=1\times {{2}^{\left( 15-1 \right)}} \\ & ={{2}^{14}} \\ & =16384 \end{align} Hence, on${{15}^{th}}$ day the person puts aside$\16,384$.