Answer
$a_{8}=\frac{3}{64}$
Work Step by Step
The nth term of a geometric sequence can be found using the formula:
$a_n=a_1(r^{n-1})$
where
r= common ratio
$a_1$ = first term
$a_n$ = nth term
n = term number
Substitute the given values of $a_1$, n, and $r$ to find:
$a_{8}=6(\frac{1}{2})^{8-1}
\\a_{8}=6(\frac{1}{2})^{7}
\\a_{8}=6(\frac{1}{128})
\\a_8=\frac{6}{128}
\\a_{8}=\frac{3}{64}$