## Thinking Mathematically (6th Edition)

False The corrected statement is: $4^{-2} \gt 4^{-3}$
The statement is false because: $4^{-2} = \dfrac{1}{4^2} = \dfrac{1}{16}$ $4^{-3} = \dfrac{1}{4^3} = \dfrac{1}{64}$ $\dfrac{1}{16} \not \lt \dfrac{1}{64}$ The corrected statement would be: $4^{-2} \gt 4^{-3}$