Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.6 Exponents and Scientific Notation - Exercise Set 5.6 - Page 321: 133


False The corrected statement is: $4^{-2} \gt 4^{-3}$

Work Step by Step

The statement is false because: $4^{-2} = \dfrac{1}{4^2} = \dfrac{1}{16}$ $4^{-3} = \dfrac{1}{4^3} = \dfrac{1}{64}$ $\dfrac{1}{16} \not \lt \dfrac{1}{64}$ The corrected statement would be: $4^{-2} \gt 4^{-3}$
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