## Thinking Mathematically (6th Edition)

Published by Pearson

# Chapter 5 - Number Theory and the Real Number System - 5.5 Real Numbers and Their Properties; Clock Addition - Exercise Set 5.5 - Page 310: 86

#### Answer

No, it does not. The positions (or order) of the factors were changed, so the statement illustrates the commutative property of multiplication.

#### Work Step by Step

The commutative property of multiplication states that for any real numbers $a, b,$ and $c$: $a \cdot (b \cdot c)= a \cdot (c \cdot b)$ The associative property of multiplication states that for any real numbers $a, b,$ and $c$: $a \cdot (b \cdot c)= (a \cdot b) \cdot c$ Thus, the given statement illustrates the commutative property as the positions of $c$ and $b$ were switched.

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