Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.4 The Irrational Numbers - Exercise Set 5.4 - Page 297: 82

Answer

) Consider the provided formula. $h=4\sqrt{x}+35$ Substitute $0$ for $x$ and find $h$, that is., $\begin{align} & h=4\sqrt{0}+35 \\ & =0+35 \\ & =35 \end{align}$ So, the value of $h$ is $35\text{ cm}$ (b) Consider the provided formula. $h=4\sqrt{x}+35$ Substitute $9$ for $x$ and find $h$, that is., $\begin{align} & h=4\sqrt{9}+35 \\ & =4\sqrt{{{3}^{2}}}+35 \\ & =4\left( 3 \right)+35 \\ & =47 \end{align}$ So, the value of $h$is $47\text{ cm}$. (c) Consider the provided formula. $h=4\sqrt{x}+35$ Substitute $14$ for $x$ and find $h$, that is., $h=4\sqrt{14}+35$ Now, use a calculator to find the value. That is., $h=49.96$ So, the value of $h$ is $\text{50 cm}$ (d) From the provided graph check the corresponding values on $y\text{-axis}$ for both curves for $x=0,9,14$. Also, write the values as calculated in above parts.
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