Thinking Mathematically (6th Edition)

Published by Pearson

Chapter 5 - Number Theory and the Real Number System - 5.4 The Irrational Numbers - Concept and Vocabulary Check - Page 295: 4

Answer

$\sqrt{49\cdot 6} = \sqrt{\underline{49}} \cdot \sqrt{\underline{6}} = \underline{7\sqrt6}$

Work Step by Step

We can break the two numbers being multiplied into two separate radicals, and then we can simplify further. $\sqrt{49\cdot 6} = \sqrt{\underline{49}} \cdot \sqrt{\underline{6}} = \underline{7\sqrt6}$

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