Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.4 The Irrational Numbers - Concept and Vocabulary Check - Page 295: 4


$\sqrt{49\cdot 6} = \sqrt{\underline{49}} \cdot \sqrt{\underline{6}} = \underline{7\sqrt6}$

Work Step by Step

We can break the two numbers being multiplied into two separate radicals, and then we can simplify further. $\sqrt{49\cdot 6} = \sqrt{\underline{49}} \cdot \sqrt{\underline{6}} = \underline{7\sqrt6}$
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