Thinking Mathematically (6th Edition)

Published by Pearson

Chapter 5 - Number Theory and the Real Number System - 5.3 The Rational Numbers - Exercise Set 5.3 - Page 284: 1

Answer

$\dfrac{2}{3}$

Work Step by Step

Reduce to lowest terms by factoring the numerator and the denominator and then cancelling common factors: $\require{cancel}=\dfrac{2(5)}{3(5)} \\=\dfrac{2\cancel{(5)}}{3\cancel{(5)}} \\=\dfrac{2}{3}$

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