Answer
$9348 = 111140_{\text{six}}$
Work Step by Step
The place values for base six are $...,6^6, 6^5, 6^4, 6^3, 6^2, 6^1, 1$.
The place values that are less than or equal to $9348$ are $6^5, 6^4, 6^3, 6^2, 6^1, 1$.
Divide $9348$ by $6^5$ or $7776$:
$9348 \div 7776 = 1$ remainder $1572$
Divide the remainder $1572$ by $6^4$ or $1296$:
$1572 \div 1296 =1$ remainder $276$
Divide the remainder $276$ by $6^3$ or $216$:
$276 \div 216 =1$ remainder $60$
Divide the remainder $60$ by $6^2$ or $36$:
$60 \div 36 = 1$ remainder $24$
Divide the remainder $24$ by $6^1$ or $6$:
$24 \div 6 = 4$ remainder $0$
Divide the remainder $0$ by $1$:
$0 \div 1 = 0$
Thus,
$9348 = (1 \times 6^5) + (1 \times 6^4) + (1 \times 6^3) + (1 \times 6^2) +(4 \times 6^1)+ (0 \times 1)
\\9348 = 111140_{\text{six}}$
