Chapter 4 - Number Representation and Calculation - 4.1 Our Hindu-Arabic System and Early Positional Systems - Exercise Set 4.1 - Page 219: 69

$5000.03$

RECALL: $10^{3} = 1000 \\10^{-2} = \dfrac{1}{10^2} = 0.01 \\10^{-3} = \dfrac{1}{10^3} = 0.001 \\10^{-4} =\dfrac{1}{10^4} = 0.0001$ Thus, the given expression is equivalent to: $=(5 \times 1000) + (3 \times 0.01) \\=5000+ 0.03 \\=5000.03$