Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 2 - Set Theory - Chapter 2 Test - Page 111: 9



Work Step by Step

RECALL: Set $A$ is a proper subset of set $B$ if all elements of $A$ are also elements of $B$ but $A\ne B$. In other words, all elements of A are also elements of B, but $B$ has at least one element that is not in A. The empty set is a proper subset of any non-empty set is the non-empty set has at least one element that is not in the empty set. However, the empty set is not a proper set of itself. Thus, the statement is false.
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