Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 2 - Set Theory - 2.5 Survey Problems - Exercise Set 2.5 - Page 104: 30

Answer

The number of elements for the different asked regions is shown below:

Work Step by Step

Simplify region II: \[n\left( A\cap B \right)=17\]is equal to region II\[+\]V. \[\begin{align} & \text{II}+\text{V}=17 \\ & \text{II}+5=17 \\ & \text{II}=12 \end{align}\] Then, for region IV: \[n\left( A\cap C \right)=11\]is equal to region IV\[+\]V. \[\begin{align} & \text{IV}+\text{V}=11 \\ & \text{IV}+5=11 \\ & \text{IV}=6 \end{align}\] Then, for region VI: \[n\left( B\cap C \right)=9\]is equal to region VI\[+\]V. \[\begin{align} & \text{VI}+\text{V}=9 \\ & \text{VI}+5=9 \\ & \text{VI}=4 \end{align}\] Then, for region I: \[n\left( A \right)=26\]is equal to region I\[+\]II\[+\]IV\[+\]V. \[\begin{align} & \text{I}+\text{II}+\text{IV}+\text{V}=26 \\ & 12+6+5+\text{I=26} \\ & \text{I=26}-23 \\ & \text{I}=3 \end{align}\] Then, for region III: \[n\left( B \right)=22\]is equal to region II\[+\]III\[+\]V\[+\]VI. \[\begin{align} & \text{II}+\text{III}+\text{V}+\text{VI}=22 \\ & 12+5+4+\text{III=22} \\ & \text{III=22}-21 \\ & \text{III}=1 \end{align}\] Then, for region VII: \[n\left( C \right)=25\]is equal to region IV\[+\]V\[+\]VI\[+\]VII. \[\begin{align} & \text{IV}+\text{V}+\text{VI}+\text{VII}=25 \\ & 6+5+4+\text{VII=25} \\ & \text{VII=25}-15 \\ & \text{VII}=10 \end{align}\] Then, for region VIII: \[\begin{align} & \text{VIII}=42-n\left( A\cup B\cup C \right) \\ & =42-\left( 3+12+1+6+5+4+10 \right) \\ & =42-41 \\ & =1 \end{align}\]
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.