Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 2 - Set Theory - 2.4 Set Operations and Venn Diagrams with Three Sets - Exercise Set 2.4 - Page 92: 45

Answer

The Venn diagram is as follows
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Work Step by Step

First, we find the four intersections of the provided sets: \[\begin{align} & A\cap B=\left\{ {{x}_{3}},\ {{x}_{9}} \right\}\cap \left\{ {{x}_{1}},\ {{x}_{2}},\ {{x}_{3}},\ {{x}_{5}},\ {{x}_{6}} \right\} \\ & =\left\{ {{x}_{3}} \right\} \end{align}\] \[\begin{align} & B\cap C=\left\{ {{x}_{1}},\ {{x}_{2}},\ {{x}_{3}},\ {{x}_{5}},\ {{x}_{6}} \right\}\cap \left\{ {{x}_{3}},\ {{x}_{4}},\ {{x}_{5}},\ {{x}_{6}},\ {{x}_{9}} \right\} \\ & =\left\{ {{x}_{3}},\ {{x}_{5}},\ {{x}_{6}} \right\} \end{align}\] \[\begin{align} & A\cap C=\left\{ {{x}_{3}},\ {{x}_{9}} \right\}\cap \left\{ {{x}_{3}},\ {{x}_{4}},\ {{x}_{5}},\ {{x}_{6}},\ {{x}_{9}} \right\} \\ & =\left\{ {{x}_{3}},\ {{x}_{9}} \right\} \end{align}\] \[\begin{align} & A\cap B\cap C=\left\{ {{x}_{3}},\ {{x}_{9}} \right\}\cap \left\{ {{x}_{1}},\ {{x}_{2}},\ {{x}_{3}},\ {{x}_{5}},\ {{x}_{6}} \right\}\cap \left\{ {{x}_{3}},\ {{x}_{4}},\ {{x}_{5}},\ {{x}_{6}},\ {{x}_{9}} \right\} \\ & =\left\{ {{x}_{3}} \right\} \end{align}\] Now, place the elements in the regions formed by the above intersections: First, place the elements of \[A\cap B\cap C=\left\{ {{x}_{3}} \right\}\] in the innermost region V. Then, place those elements of \[A\cap B\]in the region II, which do not belong to the region V, which are 5 and 6. Place the elements of \[A\cap C\]in the region IV, which donot belong to the region V, this region is empty since 4 already came in region V. Then, place the elements of \[B\cap C\]in the region VI, which do not belong to the region V. So, it contains 7 only. Then, put the remaining elements of sets A, B, and C in the regionsI, III, and VII, respectively. So region I contains 8, region III contains 1 and 2, and region VII contains 3 only. Finally, region VIII contains the remaining elements of the set U. So, all the elements of the set U are used up. So, it contains only 9.
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