## Thinking Mathematically (6th Edition)

Published by Pearson

# Chapter 2 - Set Theory - 2.2 Subsets - Exercise Set 2.2: 76

#### Answer

$\{\emptyset\} \in \{\emptyset, \{\emptyset\}\}$ is true

#### Work Step by Step

$\{\emptyset\} \in \{\emptyset, \{\emptyset\}\}$ This is correct. Let's say $A=\{\emptyset\}$ and then substitute: $A \in \{\emptyset, A\}$ This makes it clear, as $A$ is an element of a set that contains $A$.

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