Answer
See below.
Work Step by Step
$s$ shaves all those men and only those men who don't shave themselved, thus he doesn't shave himself, thus $s\in B$, and hence $s\notin A$.
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 2 - Set Theory - 2.1 Basic Set Concepts - Exercise Set 2.1 - Page 60: 136
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
