Answer
$10.69\%$
Work Step by Step
$\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$.
Hence $z_1=\frac{164-200}{15}=-2.4, z_2=\frac{182-200}{15}=-1.2$.
Then the answer, using the table is: $11.51-0.82=10.69\%$
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