Answer
See below.
Work Step by Step
The margin of error of a sample size $n$ is a $95\%$ probability that a sample lies within the margin of error which is $\pm\frac{1}{\sqrt n}\cdot 100\%$
a) Hence here the margin of error: $\pm\frac{1}{\sqrt {100}}\cdot 100\%=\pm10\%$
b) Thus we can be $95\% $confident that between that between $60-10=50\%$ and $60+10=70\%$ of all students are very satisfied with their professors.
