Answer
$\approx0.85$
Work Step by Step
$\sum x=23$, $\sum y=18$, $\sum xy=83$, $\sum x^2=115$, $\sum y^2=64$ $n=6$(the number of data points)
Thus the correlation coefficient is: $\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{n(\sum x^2)-(\sum x)^2}\sqrt{n(\sum y^2)-(\sum y)^2}}=\frac{6(83)-(23)(18)}{\sqrt{6(115)-(23)^2}\sqrt{6(64)-(18)^2}}\approx0.85$ where
