Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 12 - Statistics - 12.5 Problem Solving with the Normal Distribution - Exercise Set 12.5 - Page 821: 45

Answer

$\approx630$

Work Step by Step

Using the table, the z-score corresponding to the $90$th percentile is $\approx1.3$. $\text{z-score}=\frac{\text{data item-mean}}{\text{standard deviation}}$. $\text{data item}=\text{z-score}\cdot{\text{standard deviation}}+\text{mean}$ Hence here the data item: $1.3\cdot100+500=630$
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