Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 12 - Statistics - 12.4 The Normal Distribution - Exercise Set 12.4 - Page 814: 69

Answer

See below.

Work Step by Step

The margin of error of a sample size $n$ is a $95\%$ probability that a sample lies within the margin of error which is $\pm\frac{1}{\sqrt n}\cdot 100\%$ a) Hence here the margin of error: $\pm\frac{1}{\sqrt {4000}}\cdot 100\%\approx\pm1.6\%$ b) Thus we can be $95\% $confident that between $60.2-1.6=58.8\%$ and $60.2+1.6=61.8\%$ of the population tuned into the final episode.
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