Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 12 - Statistics - 12.2 Measures of Central Tendency - Exercise Set 12.2 - Page 791: 15


median = $95$

Work Step by Step

Arrange the scores from least to greatest to obtain: $91, 93, 95, 95, 97, 99$ There are six numbers. The middle numbers are the third and the fourth scores, which are both 95. The median will be the mean of these two numbers. Thus, median = $\dfrac{95+95}{2} = \dfrac{190}{2} = 95$
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