Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - Chapter Summary, Review, and Test - Review Exercises - Page 759: 45

Answer

$\frac{1}{24}$

Work Step by Step

We know that $probability=\frac{\text{number of favorable outcomes}}{\text{number of all outcomes}}$ The number of all outcomes is $4!=24$, out of these $1$ corresponds to the desirable order. Hence here the probability is $\frac{1}{24}$
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