Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.4 Fundamentals of Probability - Exercise Set 11.4 - Page 717: 67

Answer

$\frac{1}{6}$

Work Step by Step

P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no.\ of\ outcomes}$ We use the data in the table from the textbook to find the probability of a given education level. A total of 174 million people were included in the US Census Bureau study. E: Had less than four years of high school. Favorable outcomes= {29} P(E) = $\frac{29}{174}$ = $\frac{1}{6}$
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