Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.1 The Fundamental Counting Principle - Exercise Set 11.1 - Page 694: 30



Work Step by Step

The number of ways in which a series of successive things can occur is found by multiplying the number of ways in which each thing can occur. ------------ We want to see in how many ways we can choose the 1st digit, .... ( 9 ways, one of 1-9, can not be 0) the 2nd digit, .... ( 10 ways, one of 0-9) the 3rd digit, .... ( 10 ways, one of 0-9) the 4th digit, .... ( 5 ways, one of $\{1,3,5,7,9\}$, an odd digit) Since this is a series of successive choices, we apply the FTC. Total= 9$\times$10$\times$10$\times$5=4,500
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.