Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 10 - Geometry - Chapter Summary, Review, and Test - Review Exercises - Page 683: 63

Answer

$A \approx 58^o$

Work Step by Step

RECALL: In a right triangle, $\sin{A} = \dfrac{\text{length of opposite side}}{\text{length of hypotenuse}}$ $\cos{A} = \dfrac{\text{length of adjacent side}}{\text{length of hypotenuse}}$ $\tan{A} = \dfrac{\text{length of opposite side}}{\text{length of adjacent side}}$ Use the sine formula above to obtain: $\sin{A} = \dfrac{17}{20}$ Use the inverse sine function to obtain: $A = \sin^{-1}{(\frac{17}{20})} \\A = 58.21166938^o \\A \approx 58^o$
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