Answer
The cost to cover a rectangular floor is\[\$650\].
Work Step by Step
It is required to determine the area (Ar) of rectangular floor in feet and the area of square tile.
Compute the area of the rectangular floor as mentioned below:
\[\begin{align}
& Ar=40\text{ ft}\times 50\text{ ft} \\
& =2000\text{ f}{{\text{t}}^{\text{2}}}
\end{align}\]
Compute the area (As) of the square tile as shown below:
\[\begin{align}
& As=2\text{ ft}\times 2\text{ ft} \\
& =4\text{ f}{{\text{t}}^{2}}
\end{align}\]
Then it is required to compute the total number of tiles needed to cover a rectangular floor which is as shown below:
\[\begin{align}
& \text{Number of tiles}=\frac{Ar}{As} \\
& =\frac{2000\text{ f}{{\text{t}}^{2}}}{4\text{ f}{{\text{t}}^{2}}} \\
& =500\text{ tiles}
\end{align}\]
Then, it is required to compute the number of packages. 1 package contains 10 tiles and the cost of a package is\[\$13\]. Compute the number of packages as shown below:
\[\begin{align}
& \text{Number of packages}=\frac{500\text{ tiles}}{10\text{ tiles}} \\
& =50
\end{align}\]
Finally, the cost to cover a rectangular floor can be computed by multiplying the cost of tiles, by the area of the rectangular floor in square feet as shown below:
\[\begin{align}
& cost=50\text{ packages}\times \$13\\&=\$650\end{align}\]
