Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 10 - Geometry - Chapter Summary, Review, and Test - Review Exercises - Page 681: 20


$c=10$ ft

Work Step by Step

RECALL: The Pythagorean Theorem states that in a right triangle, $c^2=a^2+b^2$ where: $a$ and $b$ are the lengths of the legs (non-hypotenuse sides) $c$ is the length of the hypotenuse Use the Pythagorean Theorem with a = 8 and b = 6 to obtain: $c^2 = 8^2 + 6^2 \\c^2=64+36 \\c^2=100$ Take the square root of both sides to obtain: $c = \pm \sqrt{100} \\c = \pm \sqrt{10^2} \\c = \pm 10$ Since $c$ represents a length, it cannot be negative. Thus, $c= 10 $ ft
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