## Thinking Mathematically (6th Edition)

$\sin{A} = \frac{6}{10}=\frac{3}{5} \\\cos{A} = \frac{8}{10} = \frac{4}{5} \\\tan{A} = \frac{6}{8} = \frac{3}{4}$
RECALL: In a right triangle, $\sin{A} = \dfrac{\text{length of opposite side}}{\text{length of hypotenuse}} \\\cos{A} = \dfrac{\text{length of adjacent side}}{\text{length of hypotenuse}} \\\tan{A} = \dfrac{\text{length of opposite side}}{\text{length of adjacent side}}$ Use the formulas above to obtain: $\sin{A} = \frac{6}{10}=\frac{3}{5} \\\cos{A} = \frac{8}{10} = \frac{4}{5} \\\tan{A} = \frac{6}{8} = \frac{3}{4}$