Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 10 - Geometry - 10.6 Right Triangle Trigonometry - Exercise Set 10.6 - Page 665: 2


$\sin{A} = \frac{6}{10}=\frac{3}{5} \\\cos{A} = \frac{8}{10} = \frac{4}{5} \\\tan{A} = \frac{6}{8} = \frac{3}{4}$

Work Step by Step

RECALL: In a right triangle, $\sin{A} = \dfrac{\text{length of opposite side}}{\text{length of hypotenuse}} \\\cos{A} = \dfrac{\text{length of adjacent side}}{\text{length of hypotenuse}} \\\tan{A} = \dfrac{\text{length of opposite side}}{\text{length of adjacent side}}$ Use the formulas above to obtain: $\sin{A} = \frac{6}{10}=\frac{3}{5} \\\cos{A} = \frac{8}{10} = \frac{4}{5} \\\tan{A} = \frac{6}{8} = \frac{3}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.