Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 1 - Problem Solving and Critical Thinking - Chapter Summary, Review, and Test - Review Exercises - Page 43: 14

Answer

See below.

Work Step by Step

a) $(2(1)+4)/2-2=1$ $(2(2)+4)/2-2=2$ $(2(3)+4)/2-2=3$ $(2(4)+4)/2-2=4$ $(2(5)+4)/2-2=5$ Conjecture: the result is the original number. b) Proof: for any $n$, the procedure is as follows: $n$, then $2n$, then $2n+4$, then $(2n+4)/2=n+2)$, then $(n+2)-2=n$, thus we always get back the original number.
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