#### Answer

6 ways

#### Work Step by Step

We have 4 different people, and we need to select 2 speakers for an event.
For convenience, we'll refer to those people as A, B, C, and D.
If we select A, we can select either B, C, or D to go as well, which means that there are 3 ways to select the members so that A goes.
If we don't select A, and we select B, we can select either C or D to go with as well, which means that there are 2 ways to select the members so that A doesn't go and B goes.
If neither A nor B goes, the only combination remaining is for both C and D to go.
This gives us a total of $3+2+1=6$ ways to select the speakers.