Answer
Not Reflixive
Symmetric
Not transitive
Work Step by Step
a) counter example : if x=1,y=0 then xCx = $\ 1^2 + 1^2 ≠ 1 $ Hence not reflixive
b) suppose x,y are particular but arbitrary chosen integers we need to show if xCy then yCx
xCy = $\ x^2 + y^2 = 1 $
xCy = $\ y^2 + x^2 = 1 $ $ commutive $ $ law$
xCy = yCx $\ that's what we need to show$
c) Counterexample let x=1,y=0,z=1
xCy = $\ 1^2 + 0^2 = 1> True $
yCz $\ 0^2 + 1^2 = 1> True $
But xCz $\ 1^2 + 1^2 ≠ 1> $ hence not transtive
