Answer
$a-\,\,p_{1}(2, y) = 2\,\,\,,\,\,p_{1}(5, x) = 5 \\
Range\,of\,p_{1}=\left \{ 2,3,5 \right \}=A\\
b- \\
p_{2}(2,y)=y\,\,\,\,,p_{2}(5,x)=x\\
Range\,of\,p_{2}=\left \{ x,y \right \}=B\\$
Work Step by Step
$
for\,\,each\,\,pair\,\,(a, b)\in A \times B \\
p_{1}(a, b) = a\,\,,and\,\,\,p_{2}(a, b) = b.\\
A=\left \{ 2,3,5 \right \},B=\left \{ x,y \right \}\\
a-\,\,p_{1}(2, y) = 2\,\,\,,\,\,p_{1}(5, x) = 5 \\
A\times B=\left \{ (2,x),(2,y),(3,x),(3,y),(5,x),(5,y) \right \}\\
p_{1}(2,x)=2 \,\,\,\,,p_{1}(2,y)=2 \\
p_{1}(3,x)=3 \,\,\,\,,p_{1}(3,y)=3 \\
p_{1}(5,x)=5 \,\,\,\,,p_{1}(5,y)=5 \\
Range\,of\,p_{1}=\left \{ 2,3,5 \right \}=A\\
b-p_{2}(2,y)=y\,\,\,\,,p_{2}(5,x)=x\\
p_{2}(2,x)=x \,\,\,\,,p_{2}(2,y)=y \\
p_{2}(3,x)=x \,\,\,\,,p_{2}(3,y)=y \\
p_{2}(5,x)=x \,\,\,\,,p_{2}(5,y)=y \\
Range\,of\,p_{2}=\left \{ x,y \right \}=B\\
$