Answer
See below.
Work Step by Step
Since $n$ ends in $0$, we can write $n=10m+0$ where $m$ is a nonnegative integer. Thus $n=5(2m)$ and $5|n$ (2m is an integer).
Discrete Mathematics with Applications 4th Edition
by Epp, Susanna S.
Published by
Cengage Learning
ISBN 10:
0-49539-132-8
ISBN 13:
978-0-49539-132-6
Chapter 4 - Elementary Number Theory and Methods of Proof - Exercise Set 4.3 - Page 179: 44
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