Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 4 - Elementary Number Theory and Methods of Proof - Exercise Set 4.3 - Page 177: 3


Yes, $5|0$ because $0=5\times0$ and $0$ is an integer.

Work Step by Step

By definition, for two integers $a$ and $b$ where $a\ne0$, $a|b$ if and only if $b=ka$ for some integer $k$. Here, $a=5$, $b=0$, and $k=0$. Note that it is okay for $k$ to equal zero: the only number that is not allowed to equal zero is $a$.
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