Yes, $5|0$ because $0=5\times0$ and $0$ is an integer.
Work Step by Step
By definition, for two integers $a$ and $b$ where $a\ne0$, $a|b$ if and only if $b=ka$ for some integer $k$. Here, $a=5$, $b=0$, and $k=0$. Note that it is okay for $k$ to equal zero: the only number that is not allowed to equal zero is $a$.